adicn/phpcms/modules/content/fields/linkage/field_edit_form.inc.php

<?php defined('IN_PHPCMS') or exit('No permission resources.');?>
<table cellpadding="2" cellspacing="1" width="98%">
	<tr> 
      <td>菜单ID</td>
      <td><input type="text" id="linkageid" name="setting[linkageid]" value="<?php echo $setting['linkageid'];?>" size="5"> 
	  <input type='button' value="在列表中选择" onclick="omnipotent('selectid','?m=admin&c=linkage&a=public_get_list','在列表中选择')" class="button">
		请到导航 扩展 > 联动菜单 > 添加联动菜单</td>
    </tr>
	<tr>
	<td>显示方式</td>
	<td>
      	<input name="setting[showtype]" value="0" type="radio" <?php if($setting['showtype']==0) echo 'checked';?>>
        只显示名称
        <input name="setting[showtype]" value="1" type="radio" <?php if($setting['showtype']==1) echo 'checked';?>>
        显示完整路径  
        <input name="setting[showtype]" value="2" type="radio" <?php if($setting['showtype']==2) echo 'checked';?>>
        返回联动菜单id
       <input name="setting[showtype]" value="3" type="radio" <?php if($setting['showtype']==3) echo 'checked';?>>
        返回菜单层级数组	 		
	</td></tr>
	<tr> 
      <td>路径分隔符</td>
      <td><input type="text" name="setting[space]" value="<?php echo $setting['space'];?>" size="5" class="input-text"> 显示完整路径时生效</td>
    </tr>	
	<tr> 
      <td>是否作为筛选字段</td>
      <td>
	  <input type="radio" name="setting[filtertype]" value="1" <?php if($setting['filtertype']) echo 'checked';?> /> 是 
	  <input type="radio" name="setting[filtertype]" value="0" <?php if(!$setting['filtertype']) echo 'checked';?>/> 否
	  </td>
    </tr>	
</table>